How to calculate the difference between two timestamps?

[Matthew Lincoln]

In a shell script I would like to calculate the difference between two timestamps.
It should look like similar to:


mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)


However the script above does not work.

Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?

Matthew

[Vilmos Soti]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`

Try this:

$ mystart=`date +%s`

Post by Matthew Lincoln
....
do something
....
myend=`date`

Ditto. If you use the %s parameter, then you will get the diff between
the two calls in seconds. Then you can easily manipulate that.

Vilmos

[s***@gmail.com]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?
Matthew

First, you have to construct timestamps, not dates.
In some cases, date don't have format option %s in some versions.
Then you can get timestamp with gnu awk with systime() or mktime()
function as following:
awk 'BEGIN {print systime()}'
So you code will be following:

start="$(awk 'BEGIN {print systime()})'" # or date +"%s"
do_something
end="$(awk 'BEGIN {print systime()})'" # or date +"%s"
diff="$(awk 'BEGIN {print strftime("%Y %m %d %H %M %S", '$(( ${end} - $
{start} ))')}')"
echo "${diff}"


Regards,
Jakub

[s***@gmail.com]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?
Matthew

First, you have to convert dates to timestamps.
In some date versions, the formatter options %s is missing. Then you
can get timestamps with gnu awk version with date functions.
So your code will be following:

start="$(awk 'BEGIN {print systime()}')"
do_something
end="$(awk 'BEGIN {print systime()}')"
diff="$(awk 'BEGIN {print strftime("%Y %m %d %H %M %S", '$(( ${end} - $
{start} ))')}')"
echo "${diff}"

Regards,
Jakub

[Javi]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?
Matthew

why not taking the date with seconds (date +%s ) and then transform
the seconds diff on days / hours .. ?

[Joachim Gann]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.

GNU date (unix time in seconds):
$ date --date=now +%s
1212330415

rest is a piece of cake

[Bill Marcum]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two
mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d
above then contain e.g. "35" or does it contain a value modulo 31
(here: 4) ?
Matthew

calcdiff is not a standard command. If your system has a calcdiff
command, arguments are usually not enclosed in parentheses or separated
by commas. If you have the GNU date command, you can write:
mystart=$(date +%s)
...
myend=$(date +%s)
elapsed=$((myend - mystart))
echo elapsed time="$elapsed" seconds

[Unruh]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`

mystart=`date +%s`

Post by Matthew Lincoln
....
do something
....
myend=`date`

myend=`date +%s`

Post by Matthew Lincoln
elapsed=calcdiff($mystart, $myend)

elapsed=$(($myend-$mystart))
hour=$(($elapsed/3600))
minute=$(($elapsed/60-60*$hour))
sec=$(($elapsed-3600*$hour-60*$minute))
echo $hour':'$minute':'$sec

Post by Matthew Lincoln
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?
Matthew

[Dave Kelly]

Post by Matthew Lincoln
In a shell script I would like to calculate the difference between two timestamps.
mystart=`date`
....
do something
....
myend=`date`
elapsed=calcdiff($mystart, $myend)
echo elapsed time=$(elapsed +%d:%H:%M:%S)
However the script above does not work.
Further question when the runtime is greater than 31 days does %d above then contain e.g. "35"
or does it contain a value modulo 31 (here: 4) ?
Matthew

use this code snippet to calculate the difference. I did this back in
05-06

NOW=$(date -d "`lynx -dump http://www.tldp.org/timestamp.txt`" +%s)
TIMESTAMP=$(date -d "`lynx -dump -connect_timeout=20 $url/
timestamp.txt`" +%s)

if [[ "$TIMESTAMP" == "" ]] ; then
continue
fi
TIMEFRAME=$(($NOW - $TIMESTAMP))
## printf "Time frame is: %s\n" "$TIMEFRAME"
if [ "$TIMEFRAME" -gt 1209600 ] ; then
cat messagefile | mail -s "TLDP mirror update request"
$admin_email
echo $url" * "$admin_email $TIMEFRAME >> TLDPreminderlog